| from functools import lru_cache | |||||
| from itertools import product, cycle, count | |||||
| @lru_cache(maxsize=None) | |||||
| def play(p1, p2, s1=0, s2=0): | |||||
| if s2 >= 21: return 0, 1 | |||||
| w1, w2 = 0, 0 | |||||
| for die in d3: | |||||
| pN = (p1 + die) % 10 or 10 | |||||
| n2, n1 = play(p2, pN, s2, s1 + pN) | |||||
| w1, w2 = (w1 + n1), (w2 + n2) | |||||
| return w1, w2 | |||||
| text = open(0).read() | |||||
| d3 = [sum(rolls) for rolls in product(range(1, 4), repeat=3)] | |||||
| p1, p2 = [int(ln[-1]) for ln in text.splitlines()] | |||||
| state = {0: (0, p1), 1: (0, p2)} | |||||
| d100 = cycle(range(1,101)) | |||||
| for i in count(): | |||||
| score, pos = state[i % 2] | |||||
| pos = (pos + next(d100) + next(d100) + next(d100)) % 10 or 10 | |||||
| state[i % 2] = (score + pos, pos) | |||||
| if score + pos >= 1000: | |||||
| break | |||||
| print((i + 1) * 3 * min(state.values())[0]) | |||||
| print(max(play(p1, p2))) |